In the end of year History exam, the mean mark scored by the 30 students in Form 11A was 55% and the mean mark scored by the 25 students in Form 11B was 44%. What was the mean mark of all the students?
Question
In the end of year History exam, the mean mark scored by the 30 students in Form 11A was 55% and the mean mark scored by the 25 students in Form 11B was 44%. What was the mean mark of all the students?
Solution
To find the mean mark of all the students, we need to find the total marks scored by all the students and then divide it by the total number of students.
Step 1: Find the total marks for Form 11A The mean mark for Form 11A is 55%. This means that the total marks scored by all the students in Form 11A is 55 * 30 = 1650.
Step 2: Find the total marks for Form 11B Similarly, the mean mark for Form 11B is 44%. This means that the total marks scored by all the students in Form 11B is 44 * 25 = 1100.
Step 3: Find the total marks for all students Now, add the total marks for Form 11A and Form 11B to get the total marks for all students. So, 1650 + 1100 = 2750.
Step 4: Find the total number of students The total number of students is the sum of the number of students in Form 11A and Form 11B. So, 30 + 25 = 55.
Step 5: Find the mean mark for all students Finally, divide the total marks by the total number of students to get the mean mark. So, 2750 / 55 = 50%.
Therefore, the mean mark of all the students is 50%.
Similar Questions
The average mark obtained by 40 students is 56. If the average marks of 8 students who failed the examination are 10, what are the average marks of students who passed the examination?
The mean of the marks scored by 50 students was found to be 39. Later it was found that a score of 43 was written as 23. Find the correct mean.
In a class of 40 students, the mean score of the girls is 30, the mean score of the boys is 40, and the mean score of the entire class is 32. If the score of one boy was incorrectly computed as 30 for 40, what is the correct mean score for the entire class?22 Mark For ReviewA) 31B) 31.50C) 32.25D) 36
In a test, the average marks of five students was found to be 48. Later it was discovered that the marks of one student was misread as 32 instead of 67. Find the correct average?
The arithmetic mean of the scores of a group of students in a test was 52. The brightest 20% of them secured a mean score of 80 and the dullest 25% a mean score of 31. The mean score of remaining 55% is: (approx.)?
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.