What least number must be added to 1056, so that the sum is completely divisible by 23?231821
Question
What least number must be added to 1056, so that the sum is completely divisible by 23?231821
Solution
To find the least number that must be added to 1056 to make the sum completely divisible by 23, you need to find the remainder when 1056 is divided by 23.
Step 1: Divide 1056 by 23.
1056 ÷ 23 = 45 remainder 21
This means that 1056 is 21 more than a multiple of 23.
Step 2: Subtract the remainder from 23.
23 - 21 = 2
So, the least number that must be added to 1056 to make the sum completely divisible by 23 is 2.
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