−3x 2 +x=13

Sure, let's solve the equation step by step:

1. First, rewrite the equation: -3x^2 + x = 13
2. Move 13 to the left side of the equation to set the equation to 0: -3x^2 + x - 13 = 0
3. Now, we need to solve this quadratic equation. The general form of a quadratic equation is ax^2 + bx + c = 0. The solution for x can be found using the quadratic formula: x = [-b ± sqrt(b^2 - 4ac)] / (2a)
4. In our equation, a = -3, b = 1, and c = -13.
5. Substitute these values into the quadratic formula: x = [-1 ± sqrt((1)^2 - 4*(-3)(-13))] / (2(-3))
6. Simplify under the square root: x = [-1 ± sqrt(1 - 156)] / -6
7. Since we can't take the square root of a negative number, there are no real solutions for this equation.