Knowee
Questions
Features
Study Tools

What is the power developed by a 22kΩ component with 9.0V applied to it?

Question

What is the power developed by a 22kΩ component with 9.0V applied to it?

🧐 Not the exact question you are looking for?Go ask a question

Solution

The power P developed by a component can be calculated using Ohm's law and the formula for power.

Step 1: Convert the resistance to ohms. In this case, it's already given in ohms (22kΩ = 22000Ω).

Step 2: Use Ohm's law (V = IR) to find the current I. Rearrange the formula to I = V/R.

Step 3: Substitute the given values into the formula. I = 9.0V / 22000Ω = 0.000409 A (rounded to six decimal places).

Step 4: Use the formula for power P = IV.

Step 5: Substitute the values into the formula. P = 0.000409 A * 9.0V = 0.00368 W or 3.68 mW.

So, the power developed by the 22kΩ component with 9.0V applied to it is approximately 3.68 mW.

This problem has been solved

Similar Questions

What current is flowing through a component if it develops 23MW when 23kV is applied to it?

What is the resistance of a component if it develops 23MW when 23kV is applied to it?

ind the real Power to the nearest Watt that is being dissipated by the circuit shownA. 38 WB. 66W

What is the power developed by a component that has 13A through it when has 240V applied to it?

If you complete the job in 8.0 s, what power is developed?

1/1

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.