if the sum of three consecutive natural numbers is 30, find the numbers if y is thre smaalest among the three consecutive natural numbers, then the second smallest would be

To find the three consecutive natural numbers, we can set up an equation based on the given information. Let's assume that the smallest number is represented by y.

According to the problem, the sum of the three consecutive natural numbers is 30. So, we can write the equation as:

y + (y+1) + (y+2) = 30

Now, let's solve this equation step by step:

1. Combine like terms: 3y + 3 = 30

2. Subtract 3 from both sides of the equation: 3y = 27

3. Divide both sides of the equation by 3: y = 9

Therefore, the smallest number (y) is 9.

To find the second smallest number, we can simply add 1 to the smallest number: Second smallest number = 9 + 1 = 10

So, the second smallest number among the three consecutive natural numbers is 10.