HLDifficulty: Multiple choice questionSodium hydroxide solution reacts with calcium chloride solution according to the following equation:2NaOH(aq) + CaCl2(aq) → 2NaCl(aq) + Ca(OH)2(s)30.0 cm3 of 0.500 mol dm–3 NaOH(aq) reacts with 20.0 cm3 of CaCl2(aq). Calculate the concentration of the CaCl2 solution (in mol dm–3).
Question
HLDifficulty: Multiple choice questionSodium hydroxide solution reacts with calcium chloride solution according to the following equation:2NaOH(aq) + CaCl2(aq) → 2NaCl(aq) + Ca(OH)2(s)30.0 cm3 of 0.500 mol dm–3 NaOH(aq) reacts with 20.0 cm3 of CaCl2(aq). Calculate the concentration of the CaCl2 solution (in mol dm–3).
Solution
To solve this problem, we need to first understand the stoichiometry of the reaction. According to the balanced chemical equation, 2 moles of NaOH react with 1 mole of CaCl2.
Step 1: Calculate the number of moles of NaOH The number of moles of NaOH can be calculated using the formula: Moles = Concentration x Volume = 0.500 mol/dm^3 x 30.0 cm^3 x (1 dm^3/1000 cm^3) = 0.015 mol
Step 2: Calculate the number of moles of CaCl2 Since 2 moles of NaOH react with 1 mole of CaCl2, the number of moles of CaCl2 will be half of the number of moles of NaOH. = 0.015 mol / 2 = 0.0075 mol
Step 3: Calculate the concentration of CaCl2 The concentration of CaCl2 can be calculated using the formula: Concentration = Moles / Volume = 0.0075 mol / 20.0 cm^3 x (1 dm^3/1000 cm^3) = 0.375 mol/dm^3
So, the concentration of the CaCl2 solution is 0.375 mol/dm^3.
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