Knowee
Questions
Features
Study Tools

To find the enthalpy of a reaction using heats of formation…Group of answer choicessubtract the product heats of formation from reactant heats of formationsubtract the reactant heats of formation from product heats of formation

Question

To find the enthalpy of a reaction using heats of formation…Group of answer choicessubtract the product heats of formation from reactant heats of formationsubtract the reactant heats of formation from product heats of formation

🧐 Not the exact question you are looking for?Go ask a question

Solution

To find the enthalpy of a reaction using heats of formation, you subtract the reactant heats of formation from the product heats of formation. This is based on Hess's Law which states that the total enthalpy change of a reaction is the sum of the enthalpy changes of the individual steps, regardless of the path taken.

Here are the steps:

  1. Write down the balanced chemical equation for the reaction.

  2. Look up the standard heats of formation for each reactant and product in the reaction. These values are usually given in tables in chemistry textbooks or online.

  3. Multiply the heat of formation of each reactant and product by its stoichiometric coefficient (the number in front of it in the balanced equation).

  4. Add up the total heat of formation for the reactants and do the same for the products.

  5. Subtract the total heat of formation of the reactants from that of the products. The result is the enthalpy change for the reaction.

Remember, a negative enthalpy change indicates an exothermic reaction (gives off heat), while a positive value indicates an endothermic reaction (absorbs heat).

This problem has been solved

Similar Questions

To find the enthalpy of a reaction using heats of formation…

Determine the enthalpy change for 7.1 g of C6H6 in the following reaction using the enthalpies of formation. (5 marks) 2C6H6 (l) + 15O2(g) 12CO2(g) + 6H2O(g)

Using heats of formation to calculate the overall heat gained or lost in a chemical reaction is really just an expression of… Group of answer choicesThe Pauli Exclusion PrincipleEinstein's Theory of RelativityHess's LawPascal's Law

Calculate the heat of the following reaction:C6H12O6 → 2C2H5OH + 2CO2Given the following heats of formation:C6H12O6                ΔH°f=  -1260 kJ/molC2H5OH                ΔH°f=  -277.7 kJ/molCO2                      ΔH°f=  -393.5 kJ/molGroup of answer choices-336.1 kJ/mol-1266 kJ/mol-22.6 kJ/mol-82.4 kJ/mol

Given the following enthalpies of formation in kJ/mol:CH4(g) = - 74.8           O3(g) = 143H2O(g) = - 242             CO2(g) = - 394what is the standard heat of reaction in kJ/mol for the reaction below?3 CH4(g) + 4 O3(g) 3 CO2(g) + 6 H2O(g)Question 6Select one:a.(3 x -394   +  6 x -242)   +   ( 3 x -74.8  +   4 x 143) b.(3 x -394   +  6 x -242)   -   ( 3 x 74.8  +   4 x  -143) c.(3 x -394   +  6 x -242)   -   ( 3 x -74.8  +   4 x 143) d.( 3 x -74.8  +   4 x  143)  -  (3 x -394   +  6 x -242)e.( 3 x -74.8  +   4 x  143)  +  (3 x -394   +  6 x -242)

1/3

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.