Sure, here is a simple Python program that uses a while loop to check if a number is a palindrome:

```python
def is_palindrome(num):
temp = num
reverse_num = 0

while num 0:
digit = num % 10
reverse_num = reverse_num * 10 + digit
num = num // 10

if temp == reverse_num:
return True
else:
return False

# Test the function
print(is_palindrome(12321)) # True
print(is_palindrome(12345)) # False
```

In this program, we first store the input number in a temporary variable. Then we use a while loop to reverse the number. In each iteration of the loop, we take the last digit of the number (using `num % 10`), add it to `reverse_num` (after shifting `reverse_num` one place to the left), and remove the last digit from `num` (using `num // 10`). Finally, we check if the original number and the reversed number are the same. If they are, the number is a palindrome; otherwise, it's not.

Question

Sure, here is a simple Python program that uses a while loop to check if a number is a palindrome:

```python
def is_palindrome(num):
    temp = num
    reverse_num = 0

while num > 0:
        digit = num % 10
        reverse_num = reverse_num * 10 + digit
        num = num // 10

if temp == reverse_num:
        return True
    else:
        return False

# Test the function
print(is_palindrome(12321))  # True
print(is_palindrome(12345))  # False
```

In this program, we first store the input number in a temporary variable. Then we use a while loop to reverse the number. In each iteration of the loop, we take the last digit of the number (using `num % 10`), add it to `reverse_num` (after shifting `reverse_num` one place to the left), and remove the last digit from `num` (using `num // 10`). Finally, we check if the original number and the reversed number are the same. If they are, the number is a palindrome; otherwise, it's not.

Knowee AI · Accepted Answer

Sure, here is a simple Python program that uses a while loop to check if a number is a palindrome:

```python
def is_palindrome(num):
    temp = num
    reverse_num = 0

while num > 0:
        digit = num % 10
        reverse_num = reverse_num * 10 + digit
        num = num // 10

if temp == reverse_num:
        return True
    else:
        return False

# Test the function
print(is_palindrome(12321))  # True
print(is_palindrome(12345))  # False
```

In this program, we first store the input number in a temporary variable. Then we use a while loop to reverse the number. In each iteration of the loop, we take the last digit of the number (using `num % 10`), add it to `reverse_num` (after shifting `reverse_num` one place to the left), and remove the last digit from `num` (using `num // 10`). Finally, we check if the original number and the reversed number are the same. If they are, the number is a palindrome; otherwise, it's not.

Susi loves playing with numbers and exploring their unique properties. One day, she learned about palindromic numbers and decided to write a program to check if a given number is a palindrome or not. Can you help her accomplish this task using a while loop?

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