What is the output of the following code? (Choose all that apply) 1: interface Aquatic { 2: public default int getNumberOfGills(int input) { return 2; } 3: } 4: public class ClownFish implements Aquatic { 5: public String getNumberOfGills() { return "4"; } 6: public String getNumberOfGills(int input) { return "6"; } 7: public static void main(String[] args) { 8: System.out.println(new ClownFish().getNumberOfGills(-1)); 9: } 10: } *1 pointA. 2B. 4C. 6D. The code will not compile because of line 5.E. The code will not compile because of line 6.F. The code will not compile because of line 8.
Question
What is the output of the following code? (Choose all that apply) 1: interface Aquatic { 2: public default int getNumberOfGills(int input) { return 2; } 3: } 4: public class ClownFish implements Aquatic { 5: public String getNumberOfGills() { return "4"; } 6: public String getNumberOfGills(int input) { return "6"; } 7: public static void main(String[] args) { 8: System.out.println(new ClownFish().getNumberOfGills(-1)); 9: } 10: } *1 pointA. 2B. 4C. 6D. The code will not compile because of line 5.E. The code will not compile because of line 6.F. The code will not compile because of line 8.
Solution
The output of the code will be "6".
Here's the step by step explanation:
-
The interface
Aquaticdefines a default methodgetNumberOfGills(int input)that returns 2. -
The class
ClownFishimplementsAquaticand overrides the methodgetNumberOfGills(int input)to return "6". It also has another methodgetNumberOfGills()that returns "4", but this method is not called in themainmethod. -
In the
mainmethod,getNumberOfGills(-1)is called on a newClownFishobject. Since the input is an integer, the methodgetNumberOfGills(int input)in theClownFishclass is called, not the method in theAquaticinterface. -
Therefore, the output will be "6".
So, the correct answer is C. 6.
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