A pebble is dropped from rest from the top of a tall cliff and falls 4.9 m after 1.0 s has elapsed. How much farther does it drop in the next 2.0 s? (Take g = 9.8 m/s2)9.8 m19.6 m39.2 m44 m
Question
A pebble is dropped from rest from the top of a tall cliff and falls 4.9 m after 1.0 s has elapsed. How much farther does it drop in the next 2.0 s? (Take g = 9.8 m/s2)9.8 m19.6 m39.2 m44 m
Solution
To find out how much farther the pebble drops in the next 2.0 seconds, we can use the equation of motion for free fall:
d = (1/2) * g * t^2
where d is the distance, g is the acceleration due to gravity, and t is the time.
Given that the pebble falls 4.9 m in the first 1.0 second, we can substitute these values into the equation:
4.9 = (1/2) * 9.8 * (1.0)^2
Simplifying the equation, we find:
4.9 = 4.9
This confirms that our calculation is correct.
Now, to find the distance the pebble drops in the next 2.0 seconds, we can substitute the new time value into the equation:
d = (1/2) * 9.8 * (2.0)^2
Simplifying the equation, we find:
d = 19.6
Therefore, the pebble drops an additional 19.6 meters in the next 2.0 seconds.
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