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Beam is cantiliver i.e one end fix other end free . At the free end there is a point load of 300 pound and span of beam is 6 feet.Do the following(a) Max Stresses ( bending ) and Stresses at Corners , top and bottom of X-Sections (b) Max Shear Stress within the sections and shear stress at 1/4 of x-section. Draw shear flow of X-SectionsTry to keep weight of x section same . Preferably depth also. The x-sections areRectangular W or IChannelTZCircle

Question

Beam is cantiliver i.e one end fix other end free . At the free end there is a point load of 300 pound and span of beam is 6 feet.Do the following(a) Max Stresses ( bending ) and Stresses at Corners , top and bottom of X-Sections (b) Max Shear Stress within the sections and shear stress at 1/4 of x-section. Draw shear flow of X-SectionsTry to keep weight of x section same . Preferably depth also. The x-sections areRectangular W or IChannelTZCircle

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Solution

This is a complex engineering problem that involves calculating the maximum bending stresses, shear stresses, and shear flow in a cantilever beam under a point load. Here's a step-by-step guide on how to solve it:

(a) Maximum Bending Stresses and Stresses at Corners, Top and Bottom of X-Sections:

  1. The formula for maximum bending stress in a beam is given by σ = My/I, where M is the moment, y is the distance from the neutral axis, and I is the moment of inertia. For a cantilever beam with a point load at the free end, the maximum moment occurs at the fixed end and is given by M = P * L, where P is the load and L is the length of the beam.

  2. For a rectangular cross-section, the distance y is half the height of the rectangle, and the moment of inertia I is given by bh^3/12, where b is the base and h is the height. Substitute these values into the stress formula to find the maximum bending stress.

  3. The stress at the corners of the cross-section is the same as the maximum bending stress because the corners are the furthest points from the neutral axis. The stress at the top and bottom of the cross-section is zero because these points are at the neutral axis.

(b) Maximum Shear Stress within the Sections and Shear Stress at 1/4 of X-Section:

  1. The formula for shear stress in a beam is given by τ = VQ/It, where V is the shear force, Q is the first moment of area, I is the moment of inertia, and t is the thickness of the section. For a cantilever beam with a point load at the free end, the maximum shear force is equal to the load P.

  2. For a rectangular cross-section, Q is given by yA, where y is the distance from the neutral axis to the centroid of the area A. The thickness t is the base b of the rectangle. Substitute these values into the shear stress formula to find the maximum shear stress.

  3. To find the shear stress at 1/4 of the cross-section, calculate Q for the area that is 1/4 of the height from the neutral axis.

(c) Shear Flow of X-Sections:

  1. The formula for shear flow in a beam is given by q = τt, where τ is the shear stress and t is the thickness of the section. Use the shear stress values calculated in part (b) to find the shear flow.

  2. Draw the shear flow on the cross-sections by representing the magnitude and direction of the shear flow at various points on the cross-section.

Remember to use consistent units throughout your calculations. The results will depend on the dimensions of the cross-sections, which were not provided in the question.

This problem has been solved

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