A quadrant has a radius of 45 m. Find the perimeter of the quadrant. Take π as 3.14.
Question
A quadrant has a radius of 45 m. Find the perimeter of the quadrant. Take π as 3.14.
Solution
To find the perimeter of a quadrant, we need to add the length of the arc (which is a quarter of the circumference of the full circle) and twice the radius (which are the two straight sides of the quadrant).
Step 1: Find the circumference of the full circle. The formula for the circumference of a circle is 2πr. Here, r is the radius, which is given as 45 m. So, the circumference is 2 * 3.14 * 45 = 282.6 m.
Step 2: Since a quadrant is a quarter of a circle, the length of the arc of the quadrant is a quarter of the full circumference. So, the length of the arc is 282.6 / 4 = 70.65 m.
Step 3: The perimeter of the quadrant is the sum of the length of the arc and twice the radius. So, the perimeter is 70.65 + 2 * 45 = 160.65 m.
So, the perimeter of the quadrant is 160.65 m.
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