what is the boiling point of a 15 m solution of NaCl? [kb= 0.52 degree C/m
Question
what is the boiling point of a 15 m solution of NaCl? [kb= 0.52 degree C/m
Solution
The boiling point of a solution can be calculated using the formula ΔTb = Kb * m, where ΔTb is the change in boiling point, Kb is the boiling point elevation constant, and m is the molality of the solution.
Given: Kb = 0.52 °C/m m = 15 m
Substitute these values into the formula:
ΔTb = Kb * m ΔTb = 0.52 °C/m * 15 m ΔTb = 7.8 °C
The boiling point of a solution is the sum of the change in boiling point (ΔTb) and the normal boiling point of the solvent. Since the solvent in this case is water, and the normal boiling point of water is 100 °C, the boiling point of the 15 m NaCl solution is:
Boiling point = 100 °C + ΔTb Boiling point = 100 °C + 7.8 °C Boiling point = 107.8 °C
So, the boiling point of a 15 m solution of NaCl is 107.8 °C.
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