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What is the equivalent annual worth of a 20-year project that has a $2 million initial cost, annual operating costs of $66,477 and annual benefits of $294,627? Assume a discount rate of 9.1%.Enter your answer in the box below in units of $ to the nearest integer. For example, if your answer is $3,482.59 then enter 3483 as your answer. The quiz allows for a 10% margin of error, so you can round up or down.

Question

What is the equivalent annual worth of a 20-year project that has a 2millioninitialcost,annualoperatingcostsof2 million initial cost, annual operating costs of 66,477 and annual benefits of 294,627?Assumeadiscountrateof9.1294,627? Assume a discount rate of 9.1%.Enter your answer in the box below in units of  to the nearest integer. For example, if your answer is $3,482.59 then enter 3483 as your answer. The quiz allows for a 10% margin of error, so you can round up or down.

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Solution

To solve this problem, we need to calculate the equivalent annual worth (EAW) of the project. The EAW is the constant annual cash flow over a specified time period that is equivalent to a given cash flow series, considering a specified interest rate.

The EAW is calculated using the formula:

EAW = (P * A/P,i,n) + (A * A/F,i,n)

where:

  • P is the present worth (initial cost of the project)
  • A is the annual worth (annual benefits - annual costs)
  • i is the interest rate (discount rate)
  • n is the number of periods (years)

In this case:

  • P = $2,000,000
  • A = 294,627294,627 - 66,477 = $228,150
  • i = 9.1% = 0.091
  • n = 20 years

First, we need to calculate the factors A/P and A/F using the formulas:

A/P = (i * (1 + i)^n) / ((1 + i)^n - 1) A/F = 1 / (((1 + i)^n - 1) / i)

Substituting the values:

A/P = (0.091 * (1 + 0.091)^20) / ((1 + 0.091)^20 - 1) = 0.0119 A/F = 1 / (((1 + 0.091)^20 - 1) / 0.091) = 0.0303

Then, we substitute these values into the EAW formula:

EAW = (2,000,0000.0119)+(2,000,000 * 0.0119) + (228,150 * 0.0303)

EAW = 23,800+23,800 + 6,913 = $30,713

So, the equivalent annual worth of the project is approximately $30,713.

This problem has been solved

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