The ratio of the amount of sugar in Container A to the amount of sugar in Container B was 13 : 18. There was to 250 g more sugar in Container A than in Container B. After an equal amount of sugar was poured out from each Container, the ratio becomes 1 : 3. What is the amount of sugar poured out from each container?

Step 1: Let's denote the initial amount of sugar in Container A as 13x and in Container B as 18x. According to the problem, we know that 13x = 18x + 250g.

Step 2: Solve the equation from step 1 for x. Subtract 18x from both sides to get -5x = 250g. Then divide both sides by -5 to find that x = -50g.

Step 3: Now we know the initial amount of sugar in each container. Container A had 13x = 13*(-50g) = -650g and Container B had 18x = 18*(-50g) = -900g. However, these values are negative, which is not possible in this context. This suggests that there might be a mistake in the problem statement, as the amount of sugar in Container A should be more than in Container B, not less.

Step 4: Assuming there was a mistake and the problem should have stated that there was 250g more sugar in Container B than in Container A, we can correct the equation in step 1 to 13x + 250g = 18x. Solving this equation gives x = 50g.

Step 5: With this corrected value for x, the initial amounts of sugar are 13x = 1350g = 650g in Container A and 18x = 1850g = 900g in Container B.

Step 6: Let's denote the amount of sugar poured out from each container as y. After this amount is poured out, the ratio of the amounts of sugar becomes 1 : 3. This gives us the equation (13x - y) / (18x - y) = 1 / 3.

Step 7: Solve the equation from step 6 for y. Multiply both sides by 3*(18x - y) to get 3*(13x - y) = 18x - y. Simplify to get 39x - 3y = 18x - y. Then add y to both sides and subtract 18x from both sides to get 21x = 2y. Divide both sides by 2 to find that y = 10.5x.

Step 8: Substitute x = 50g into the equation from step 7 to find the amount of sugar poured out from each container: y = 10.5*50g = 525g.