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For a two bit comparator circuit specify the inputs for which A > B

Question

For a two bit comparator circuit specify the inputs for which A > B

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Solution

A two-bit comparator circuit compares two two-bit numbers, A and B. Each number has two bits: A1A0 for A and B1B0 for B, where A1 and B1 are the most significant bits.

The inputs for which A > B are as follows:

  1. A1A0 = 01 and B1B0 = 00: Here, A = 1 and B = 0, so A > B.
  2. A1A0 = 10 and B1B0 = 00: Here, A = 2 and B = 0, so A > B.
  3. A1A0 = 10 and B1B0 = 01: Here, A = 2 and B = 1, so A > B.
  4. A1A0 = 11 and B1B0 = 00: Here, A = 3 and B = 0, so A > B.
  5. A1A0 = 11 and B1B0 = 01: Here, A = 3 and B = 1, so A > B.
  6. A1A0 = 11 and B1B0 = 10: Here, A = 3 and B = 2, so A > B.

So, these are the inputs for which A > B in a two-bit comparator circuit.

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