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Consider the surface F embedded in R3 such that each point on F is parameterized according to⃗p = αr⃗ p1 + r⃗ p2,where 0 < r is a fixed real number, 1 < α is a constant, and⃗p1 =cos φsin φ0 and⃗ p2 =cos (θ ) cos φcos (θ ) sin φsin (θ )where θ ∈ [0, 2π) and φ ∈ [0, 2π).Answer the following questions.[1.1] Use Mathematica to plot F embedded in R3, showing the coordinate grid on F whereconstant θ and φ are marked in different colours. Include a large, high quality graphic andidentify the coloured lines with each of the embedding coordinates.

Question

Consider the surface F embedded in R3 such that each point on F is parameterized according to⃗p = αr⃗ p1 + r⃗ p2,where 0 < r is a fixed real number, 1 < α is a constant, and⃗p1 =cos �φsin �φ0 and⃗ p2 =cos (θ ) cos �φcos (θ ) sin �φsin (θ )where θ ∈ [0, 2π) and φ ∈ [0, 2π).Answer the following questions.[1.1] Use Mathematica to plot F embedded in R3, showing the coordinate grid on F whereconstant θ and φ are marked in different colours. Include a large, high quality graphic andidentify the coloured lines with each of the embedding coordinates.

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Solution

I'm sorry, but as a text-based AI, I'm unable to create plots or graphics. However, I can guide you on how to do it in Mathematica.

First, define your functions p1 and p2:

p1[φ_] := {Cos[φ], Sin[φ], 0}
p2[θ_, φ_] := {Cos[θ] Cos[φ], Cos[θ] Sin[φ], Sin[θ]}

Then, define your surface F:

F[α_, r_, θ_, φ_] := α r p1[φ] + r p2[θ, φ]

Now, you can plot your surface F. To show the coordinate grid on F where constant θ and φ are marked in different colours, you can use the MeshFunctions option in ParametricPlot3D:

ParametricPlot3D[F[α, r, θ, φ], {θ, 0, 2 π}, {φ, 0, 2 π}, 
 MeshFunctions -> {#4 &, #5 &}, Mesh -> {20, 20}, 
 MeshStyle -> {Directive[Red, Thick], Directive[Blue, Thick]}, 
 PlotStyle -> Opacity[0.5], AxesLabel -> {"x", "y", "z"}]

In this plot, the red lines correspond to constant θ and the blue lines correspond to constant φ. You can adjust the values of α and r as needed.

This problem has been solved

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