John throws 150 coins onto a table. 60 of them show „head“, the others show „tail“. He wants the same amountof coins to show „head“ as „tail“. How many coins that show „head“ does he have to turn over?(A) 10 (B) 15 (C) 20 (D) 25 (E) 30
Question
John throws 150 coins onto a table. 60 of them show „head“, the others show „tail“. He wants the same amountof coins to show „head“ as „tail“. How many coins that show „head“ does he have to turn over?(A) 10 (B) 15 (C) 20 (D) 25 (E) 30
Solution
First, let's find out how many coins show "tail". Since John threw 150 coins and 60 of them show "head", this means that 150 - 60 = 90 coins show "tail".
John wants the same amount of coins to show "head" as "tail". This means he wants 150 / 2 = 75 coins to show "head" and 75 coins to show "tail".
Currently, there are 60 coins showing "head". To reach the desired number of 75 coins showing "head", John needs to turn over 75 - 60 = 15 coins from "tail" to "head".
So, the answer is (B) 15.
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