Select the correct answerPredict the output of below given code in C.#include <stdio.h>void Function(){ static int i=10; if(--i){ main(); printf("%d ",i); }}int main(){ Function(); return 0;}Options9 8 7 6 5 4 3 2 10 0 0 0 0 0 0 0 0 Compile time errorCode execution is clean but nothing will be printed
Question
Select the correct answerPredict the output of below given code in C.#include <stdio.h>void Function(){ static int i=10; if(--i){ main(); printf("%d ",i); }}int main(){ Function(); return 0;}Options9 8 7 6 5 4 3 2 10 0 0 0 0 0 0 0 0 Compile time errorCode execution is clean but nothing will be printed
Solution
The correct answer is "9 8 7 6 5 4 3 2 1".
Here's the step by step explanation:
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The main function calls the Function() which has a static variable 'i' initialized to 10.
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Static variables retain their values between function calls, so 'i' will not be reinitialized to 10 every time Function() is called.
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The if condition checks if --i is true. Since 'i' is 10 at first, --i will decrement it to 9 and the condition is true (non-zero), so it enters the if block.
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Inside the if block, main() is called again, which calls Function() again. Now 'i' is 9, so --i will decrement it to 8 and the condition is still true. This process repeats until 'i' is decremented to 0, at which point the condition is false and it doesn't enter the if block.
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After each call to main(), printf("%d ",i) is executed, but since this is after the recursive call to main(), these print statements will only be executed on the way back up the recursion, after 'i' has been decremented to 0 and the if condition is false.
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So the output will be the values of 'i' from 9 down to 1, printed in that order.
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