Array ChallengeHave the function ArrayChallenge(arr) take the array of numbers stored in arr and return the string true if any combination of numbers in the array (excluding the largest number) can be added up to equal the largest number in the array, otherwise return the string false. For example: if arr contains [4, 6, 23, 10, 1, 3] the output should return true because 4 + 6 + 10 + 3 = 23. The array will not be empty, will not contain all the same elements, and may contain negative numbers.ExamplesInput: [5,7,16,1,2]Output: falseInput: [3,5,-1,8,12]Output: true
Question
Array ChallengeHave the function ArrayChallenge(arr) take the array of numbers stored in arr and return the string true if any combination of numbers in the array (excluding the largest number) can be added up to equal the largest number in the array, otherwise return the string false. For example: if arr contains [4, 6, 23, 10, 1, 3] the output should return true because 4 + 6 + 10 + 3 = 23. The array will not be empty, will not contain all the same elements, and may contain negative numbers.ExamplesInput: [5,7,16,1,2]Output: falseInput: [3,5,-1,8,12]Output: true
Solution
Here is a Python solution for the problem:
def ArrayChallenge(arr):
# Sort the array in descending order
arr.sort(reverse=True)
# The largest number is the first element of the sorted array
largest = arr[0]
# The rest of the array
rest = arr[1:]
# The length of the rest of the array
n = len(rest)
# Use a bit mask to iterate through all possible combinations
for i in range(1, 2**n):
sum = 0
for j in range(n):
# If the j-th bit of i is 1, add the j-th number of the rest to the sum
if ((i >> j) & 1) == 1:
sum += rest[j]
# If the sum equals to the largest number, return "true"
if sum == largest:
return "true"
# If no combination can be found, return "false"
return "false"
This solution works by iterating through all
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