Quadrilateral ZYXW is a rhombus. If YX=2a+1𝑌𝑋=2𝑎+1 and if XW=4a –25𝑋𝑊=4𝑎 –25 , find the value of a.
Question
Quadrilateral ZYXW is a rhombus. If YX=2a+1𝑌𝑋=2𝑎+1 and if XW=4a –25𝑋𝑊=4𝑎 –25 , find the value of a.
Solution
In a rhombus, all sides are equal. Therefore, we can set the expressions for YX and XW equal to each other and solve for a.
So, 2a + 1 = 4a - 25
To solve for a, first subtract 2a from both sides to get:
1 = 2a - 25
Then, add 25 to both sides to isolate 2a:
26 = 2a
Finally, divide both sides by 2 to solve for a:
a = 13
Similar Questions
Quadrilateral ZYXW is a rhombus. Find m∠YVX𝑚∠𝑌𝑉𝑋 .
Fill in the blank question.Quadrilateral ZYXW is a rhombus. If m∠VWZ= 39°𝑚∠𝑉𝑊𝑍= 39° , find m∠VZW𝑚∠𝑉𝑍𝑊 .
The angles of a quadrilateral are x°, ( )°x 5+ , ( )°x2 25- and ( )°x 10+ .Find the value of x
In the given figure ABCD is a rhombus, the value of x is.
Fill in the blank question.Quadrilateral ABCD is a rectangle. If m∠BEA=35°,𝑚∠𝐵𝐸𝐴=35°, find m∠BAE.
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.