rect answerSIVA and Shyam are playing chess together. SIVA known the two rows in which he has to put all the pieces in but he doesn’t know how to place them. What is the probability that he puts all the pieces in the right place?Options8!/16!8!/15!8!/(2𝑥15!)(2𝑥8!)/16!

The question seems to be asking for the probability that SIVA places all the chess pieces in the correct position if he only knows the two rows where they should be placed, but not the order.

In a game of chess, each player starts with 16 pieces: 1 king, 1 queen, 2 rooks, 2 knights, 2 bishops, and 8 pawns. However, the order of the pieces within the row matters.

The total number of ways to arrange 16 unique items is 16!, or 16 factorial, which is 161514*...32*1.

If SIVA knows the two rows where the pieces should be placed, but not the order, then he has 8 pieces to arrange in each row. The number of ways to arrange 8 unique items is 8!, or 8 factorial, which is 876*...32*1.

However, since he has to arrange 8 pieces in two rows, the number of arrangements he could make is (8!)^2, or (8 factorial) squared.

The probability that he places all the pieces in the correct position is therefore the number of correct arrangements (1, since there is only one correct order of the pieces) divided by the total number of possible arrangements.

So, the correct answer is 1/(16!) or 1 divided by 16 factorial. None of the options provided match this answer.