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1.Question 1What will the following code display?ip_address = "192.168.183.51"if ip_address == "192.168.183.51":    print("You're logged in.")else:    print("Login failed, try again.")1 pointNothing"You're logged in.""Login failed, try again."Both "You're logged in." and "Login failed, try again."

Question

1.Question 1What will the following code display?ip_address = "192.168.183.51"if ip_address == "192.168.183.51":    print("You're logged in.")else:    print("Login failed, try again.")1 pointNothing"You're logged in.""Login failed, try again."Both "You're logged in." and "Login failed, try again."

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Solution

The code will display "You're logged in."

Here's the step by step explanation:

  1. The variable ip_address is assigned the string value "192.168.183.51".
  2. The if statement checks if the value of ip_address is equal to the string "192.168.183.51".
  3. Since the value of ip_address is indeed "192.168.183.51", the condition in the if statement is true.
  4. Therefore, the code within the if block is executed, which is print("You're logged in."). So, "You're logged in." is displayed.
  5. The else block is ignored because the if condition was true. If the if condition was false, then the else block would have been executed, displaying "Login failed, try again." But in this case, it doesn't happen.

This problem has been solved

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