As part of a board game, you need to spin the spinner, which is divided into equal parts. Find the probability that you get a 2 on your first spin and a number less than or equal to 5 on your second spin. Express your first answer as a fraction in simplest form, and round your percent answer to the nearest tenth.The probability is , or about %.
Question
As part of a board game, you need to spin the spinner, which is divided into equal parts. Find the probability that you get a 2 on your first spin and a number less than or equal to 5 on your second spin. Express your first answer as a fraction in simplest form, and round your percent answer to the nearest tenth.The probability is , or about %.
Solution
To answer this question, we need to know how many sections the spinner is divided into and what numbers are on the spinner. However, I'll provide a general method to solve this kind of problem.
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Find the probability of getting a 2 on the first spin. This is simply 1 divided by the total number of sections on the spinner. Let's say the spinner is divided into 'n' sections. So, the probability is 1/n.
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Next, find the probability of getting a number less than or equal to 5 on the second spin. Count how many numbers are less than or equal to 5 on the spinner. Let's say there are 'm' such numbers. So, the probability is m/n.
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Since these are independent events (the result of the first spin doesn't affect the second), you multiply the probabilities together to get the overall probability. So, the final probability is (1/n) * (m/n) = m/n^2.
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To express this as a percentage, multiply the probability by 100. So, the final answer in percentage is (m/n^2) * 100.
Remember to simplify the fraction and round the percentage to the nearest tenth as per the question's instructions.
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