Q invested 25% less than what R invested. Also P invested 20% more than what Q invested.What is investment of R if total investment done was Rs.3710?Rs.1400Rs.1300Rs.1800Rs.1650
Question
Q invested 25% less than what R invested. Also P invested 20% more than what Q invested.What is investment of R if total investment done was Rs.3710?Rs.1400Rs.1300Rs.1800Rs.1650
Solution
Let's denote the investment of R as 'r'.
According to the problem, Q invested 25% less than R. So, Q's investment is 75% of R's investment, which can be written as 0.75r.
P invested 20% more than Q. So, P's investment is 120% of Q's investment, which can be written as 1.2 * 0.75r = 0.9r.
The total investment is the sum of P, Q, and R's investments, which is r + 0.75r + 0.9r = 2.65r.
According to the problem, the total investment is Rs. 3710. So, we can set up the equation 2.65r = 3710.
Solving for r, we get r = 3710 / 2.65 = Rs. 1400.
So, R's investment is Rs. 1400.
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