A metal gas cylinder is heated from 181 K to 296 K. If the original pressure was 256 psi, what is the pressure after heating also in psi?
Question
A metal gas cylinder is heated from 181 K to 296 K. If the original pressure was 256 psi, what is the pressure after heating also in psi?
Solution
To solve this problem, we can use Gay-Lussac's Law which states that the pressure of a gas is directly proportional to its absolute temperature, provided the volume is kept constant. The formula for Gay-Lussac's Law is P1/T1 = P2/T2, where:
- P1 is the initial pressure
- T1 is the initial temperature
- P2 is the final pressure
- T2 is the final temperature
Given in the problem:
- P1 = 256 psi
- T1 = 181 K
- T2 = 296 K
- P2 = ?
We can substitute the given values into the formula and solve for P2:
256 psi / 181 K = P2 / 296 K
Cross-multiplying gives us:
P2 = (256 psi * 296 K) / 181 K
Calculating the above expression will give us the final pressure P2 in psi.
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