The vertex of a parabola given by the equation f(x) = ax^2 + bx + c is given by the point (-b/2a, f(-b/2a)).

For the equation f(x) = x^2 + 3x + 2, a = 1 and b = 3.

So, the x-coordinate of the vertex is -b/2a = -3/(2*1) = -3/2.

Substitute x = -3/2 into the equation to find the y-coordinate of the vertex:

f(-3/2) = (-3/2)^2 + 3*(-3/2) + 2 = 9/4 - 9/2 + 2 = -1/4.

So, the vertex of the equation f(x) = x^2 + 3x + 2 is (-3/2, -1/4).

Therefore, the answer is c.(-3/2, -1/4).

Question

The vertex of a parabola given by the equation f(x) = ax^2 + bx + c is given by the point (-b/2a, f(-b/2a)).

For the equation f(x) = x^2 + 3x + 2, a = 1 and b = 3.

So, the x-coordinate of the vertex is -b/2a = -3/(2*1) = -3/2.

Substitute x = -3/2 into the equation to find the y-coordinate of the vertex:

f(-3/2) = (-3/2)^2 + 3*(-3/2) + 2 = 9/4 - 9/2 + 2 = -1/4.

So, the vertex of the equation f(x) = x^2 + 3x + 2 is (-3/2, -1/4).

Therefore, the answer is c.(-3/2, -1/4).

Knowee AI · Accepted Answer

The vertex of a parabola given by the equation f(x) = ax^2 + bx + c is given by the point (-b/2a, f(-b/2a)).

For the equation f(x) = x^2 + 3x + 2, a = 1 and b = 3.

So, the x-coordinate of the vertex is -b/2a = -3/(2*1) = -3/2.

Substitute x = -3/2 into the equation to find the y-coordinate of the vertex:

f(-3/2) = (-3/2)^2 + 3*(-3/2) + 2 = 9/4 - 9/2 + 2 = -1/4.

So, the vertex of the equation f(x) = x^2 + 3x + 2 is (-3/2, -1/4).

Therefore, the answer is c.(-3/2, -1/4).

What is the vertex of f(x) = x2 + 3x + 2?Question 9Select one:a.7b.(0, 2)c.(-3/2, -1/4)d.-3/2e.None of these