How many 3-digit numbers can be formed with the digits 1,4,7,8 and 9 if the digits are not repeated?
Question
How many 3-digit numbers can be formed with the digits 1,4,7,8 and 9 if the digits are not repeated?
Solution
Sure, here is the step by step solution:
Step 1: Identify the number of digits to be used. In this case, we are forming 3-digit numbers.
Step 2: Identify the number of available unique digits. Here, we have 5 unique digits (1,4,7,8,9).
Step 3: Use the concept of permutations since the order of digits matters in a number.
Step 4: The number of ways to choose the first digit is 5 (any of the 5 digits).
Step 5: Once the first digit is chosen, we are left with 4 digits. So, the number of ways to choose the second digit is 4.
Step 6: Similarly, the number of ways to choose the third digit is 3 (since two digits have already been used).
Step 7: Multiply these values together to get the total number of 3-digit numbers.
So, the total number of 3-digit numbers that can be formed is 543 = 60.
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