The power of a lens is given by the formula P = 1/f, where f is the focal length of the lens. The focal length can be determined by the lens formula 1/f = 1/v - 1/u, where v is the image distance and u is the object distance.

In this case, the image distance v is initially the distance from the screen to the point P, which is 16 cm. When the lens is introduced, the image distance changes by 8 cm, so the new image distance v' is 16 cm - 8 cm = 8 cm.

The object distance u is the distance from the lens to the point P, which is 16 cm.

Substituting these values into the lens formula gives 1/f = 1/8 - 1/16 = 1/16 cm^-1.

Therefore, the focal length f is 16 cm.

Substituting this into the power formula gives P = 1/16 = 0.0625 D.

However, none of the options A, B, C, or D match this result. There may be a mistake in the problem or the answer choices.

Question

The power of a lens is given by the formula P = 1/f, where f is the focal length of the lens. The focal length can be determined by the lens formula 1/f = 1/v - 1/u, where v is the image distance and u is the object distance.

In this case, the image distance v is initially the distance from the screen to the point P, which is 16 cm. When the lens is introduced, the image distance changes by 8 cm, so the new image distance v' is 16 cm - 8 cm = 8 cm.

The object distance u is the distance from the lens to the point P, which is 16 cm.

Substituting these values into the lens formula gives 1/f = 1/8 - 1/16 = 1/16 cm^-1.

Therefore, the focal length f is 16 cm.

Substituting this into the power formula gives P = 1/16 = 0.0625 D.

However, none of the options A, B, C, or D match this result. There may be a mistake in the problem or the answer choices.

Knowee AI · Accepted Answer

The power of a lens is given by the formula P = 1/f, where f is the focal length of the lens. The focal length can be determined by the lens formula 1/f = 1/v - 1/u, where v is the image distance and u is the object distance.

In this case, the image distance v is initially the distance from the screen to the point P, which is 16 cm. When the lens is introduced, the image distance changes by 8 cm, so the new image distance v' is 16 cm - 8 cm = 8 cm.

The object distance u is the distance from the lens to the point P, which is 16 cm.

Substituting these values into the lens formula gives 1/f = 1/8 - 1/16 = 1/16 cm^-1.

Therefore, the focal length f is 16 cm.

Substituting this into the power formula gives P = 1/16 = 0.0625 D.

However, none of the options A, B, C, or D match this result. There may be a mistake in the problem or the answer choices.

A beam of light is converging towards a point P on a screen. A converging lens is introduced in the path of the beam at a distance 16 cm from the screen, then convergence point is shifted by 8 cm. The power of the lens is Only one correct answerA.403D403 DB.503D503 DC.254D254 DD.252D252 D

Question

Solution

Similar Questions

Upgrade your grade with Knowee