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The gravitational acceleration on the surface of the earth of radius R and mean density ρ is43GπR2ρ43Gπ2R2ρ23GπRρ43GπRρ

Question

The gravitational acceleration on the surface of the earth of radius R and mean density ρ is43GπR2ρ43Gπ2R2ρ23GπRρ43GπRρ

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Solution

It seems like there's a mistake in your question as it's not clear. However, I can tell you how to calculate the gravitational acceleration on the surface of the earth.

The gravitational acceleration on the surface of the earth can be calculated using the formula:

g = GM/R^2

where:

  • G is the gravitational constant, approximately equal to 6.674 x 10^-11 N(m/kg)^2,
  • M is the mass of the earth, and
  • R is the radius of the earth.

If you want to express the mass of the earth in terms of its density, you can use the formula for the volume of a sphere, which is V = 4/3πR^3. The mass is then density times volume, or M = ρV = ρ * 4/3πR^3.

Substituting this into the original formula gives:

g = G * ρ * 4/3πR^3 / R^2 = 4/3 * G * ρ * π * R

This is the formula for the gravitational acceleration on the surface of the earth in terms of the radius of the earth and its mean density.

This problem has been solved

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