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Larissa dives into a pool that is 8 feet deep. She touches the bottom of the pool with her hands 6 feet horizontally from the point at which she entered the water. What is the approximate angle of elevation from the point on the bottom of the pool where she touched to her entry point?

Question

Larissa dives into a pool that is 8 feet deep. She touches the bottom of the pool with her hands 6 feet horizontally from the point at which she entered the water. What is the approximate angle of elevation from the point on the bottom of the pool where she touched to her entry point?

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Solution

To solve this problem, we can use trigonometry. Specifically, we'll use the tangent function, which is defined as the ratio of the opposite side to the adjacent side in a right triangle.

  1. First, identify the sides of the triangle. The depth of the pool is the opposite side (8 feet), and the horizontal distance Larissa swam is the adjacent side (6 feet).

  2. Next, calculate the tangent of the angle. The tangent of the angle (let's call it θ) is equal to the opposite side divided by the adjacent side. So, tan(θ) = 8/6 = 1.333.

  3. Finally, to find the angle θ, we need to find the arctangent (or inverse tangent) of 1.333. Using a calculator, we find that arctan(1.333) ≈ 53.13 degrees.

So, the angle of elevation from the point on the bottom of the pool where Larissa touched to her entry point is approximately 53.13 degrees.

This problem has been solved

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