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What would be the output of the following code?import java.util.LinkedList;import java.util.Queue;class Test { public static void main (String[] args) { Queue<Integer> q=new LinkedList<Integer>(); for(int i=1;i<5;i++) { q.add(10+i); } System.out.print(q.poll()+" "+q.size()); }}

Question

What would be the output of the following code?import java.util.LinkedList;import java.util.Queue;class Test { public static void main (String[] args) { Queue<Integer> q=new LinkedList<Integer>(); for(int i=1;i<5;i++) { q.add(10+i); } System.out.print(q.poll()+" "+q.size()); }}

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Solution

The output of the code would be "11 3".

Here's the step by step explanation:

  1. A Queue of Integer type is created using LinkedList. The Queue interface is implemented by LinkedList class.

  2. A for loop is used to add elements to the queue. The loop runs from i=1 to i<5, so four elements are added to the queue: 11, 12, 13, and 14.

  3. The poll() method is used to remove and return the head of the queue. Since queues follow the FIFO (First In First Out) principle, the first element added (11) is removed and printed.

  4. The size() method is used to return the number of elements in the queue. Since one element has been removed from the original four, the size of the queue is now 3.

So, the output is "11 3".

This problem has been solved

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