Solve the triangle shown in the following figure using the Law of Sines. (Enter all angles in degrees. Round your answers to one decimal place.)6.13.170°A triangle is given.The angle at vertex A is 70°.The side opposite vertex A has length 6.1.The side opposite vertex B has length 3.1.c = ∠B = °∠C = °

To solve the triangle using the Law of Sines, we first need to find the measure of angle B. We can use the formula:

sin(B) = (b * sin(A)) / a

where: A = 70° (the given angle) a = 6.1 (the side opposite angle A) b = 3.1 (the side opposite angle B)

Substituting the given values into the formula, we get:

sin(B) = (3.1 * sin(70°)) / 6.1

Calculate the value of sin(B) and then use the inverse sine function (sin^-1) to find the measure of angle B in degrees.

Next, to find the measure of angle C, we can use the fact that the sum of the angles in a triangle is 180°. So, we have:

C = 180° - A - B

Substitute the values of A and B into this formula to find the measure of angle C.

Remember to round your answers to one decimal place.