Evaluate∫(2x + 1)1/3dx
Solution 1
To evaluate the integral ∫(2x + 1)^(1/3) dx, we can use the method of substitution. Here are the steps:
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Let u = 2x + 1. Then, du = 2dx.
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We need to express dx in terms of du. So, dx = du/2.
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Now, substitute u and dx in the original integral. We get ∫u^(1/3) * (du/2).
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Take the constant 1/2 out of the integral. We get (1/2) ∫u^(1/3) du.
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Now, we can integrate u^(1/3). The integral of u^n with respect to u is (u^(n+1))/(n+1). So, the integral of u^(1/3) with respect to u is (3/4)u^(4/3).
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Substitute this back into the integral. We get (1/2) * (3/4)u^(4/3) = (3/8)u^(4/3).
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Finally, substitute u = 2x + 1 back into the integral. We get (3/8)(2x + 1)^(4/3).
So, the integral ∫(2x + 1)^(1/3) dx = (3/8)(2x + 1)^(4/3) + C, where C is the constant of integration.
Solution 2
To evaluate the integral ∫(2x + 1)^(1/3) dx, we can use the method of substitution.
Step 1: Let u = 2x + 1. Then, du = 2dx.
Step 2: We need to express dx in terms of du. So, dx = du/2.
Step 3: Substitute u and dx in the original integral. We get ∫u^(1/3) * (du/2).
Step 4: The constant 1/2 can be taken out of the integral. So, we get (1/2)∫u^(1/3) du.
Step 5: Now, we can integrate u^(1/3) with respect to u. The integral of u^n with respect to u is (u^(n+1))/(n+1). So, the integral of u^(1/3) with respect to u is (3/4)u^(4/3).
Step 6: Substitute back u = 2x + 1. So, the integral becomes (1/2)(3/4)(2x + 1)^(4/3).
Step 7: Simplify the expression to get the final answer. The final answer is (3/8)*(2x + 1)^(4/3) + C, where C is the constant of integration.
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