the turbine of a hydroelectric power station is built below the level of a lake. The water from the lake flows down a long pipe into an automatic gate. The gate controls the mass of water passing through the blades of the turbine per second.The passing water then rotates the turbine, which then rotates a group of magnets around a coil in an alternating current generator. The magnets rotate at a constant speed that generate an electromotive force (e.m.f) of 50 000 V across a coil.In Fig 10.2 below, the running water causes the turbine to turn anticlockwise. However, the electric current drawn from the generator produces a clockwise moment that opposes the rotation of the turbine.To generate the e.m.f. of 50 000 V, the running water would need to hit the turbine blades at a certain mass per second in order to overcome the opposing moment and to turn the turbine in the anticlockwise direction. at the end the water is discharged into a river at a constant speed of 10m/s. to generate 50000V, 20A is drawn from generator, moment required to turn the turbine is 34320Nm, mass of water hitting the blades per second is 339 kg/s. calculate the amount of energy gained by the generator when 339 kg of water flows through the turbine
Question
the turbine of a hydroelectric power station is built below the level of a lake. The water from the lake flows down a long pipe into an automatic gate. The gate controls the mass of water passing through the blades of the turbine per second.The passing water then rotates the turbine, which then rotates a group of magnets around a coil in an alternating current generator. The magnets rotate at a constant speed that generate an electromotive force (e.m.f) of 50 000 V across a coil.In Fig 10.2 below, the running water causes the turbine to turn anticlockwise. However, the electric current drawn from the generator produces a clockwise moment that opposes the rotation of the turbine.To generate the e.m.f. of 50 000 V, the running water would need to hit the turbine blades at a certain mass per second in order to overcome the opposing moment and to turn the turbine in the anticlockwise direction. at the end the water is discharged into a river at a constant speed of 10m/s. to generate 50000V, 20A is drawn from generator, moment required to turn the turbine is 34320Nm, mass of water hitting the blades per second is 339 kg/s. calculate the amount of energy gained by the generator when 339 kg of water flows through the turbine
Solution
To calculate the amount of energy gained by the generator when 339 kg of water flows through the turbine, we can use the formula:
Energy = Power x Time
First, let's calculate the power generated by the generator. We know that the electromotive force (e.m.f) across the coil is 50,000 V and the current drawn from the generator is 20 A. The power can be calculated using the formula:
Power = Voltage x Current
Power = 50,000 V x 20 A Power = 1,000,000 W
Now, let's calculate the time it takes for 339 kg of water to flow through the turbine. We know that the mass of water hitting the blades per second is 339 kg/s. Therefore, the time can be calculated using the formula:
Time = Mass / Mass flow rate
Time = 339 kg / 339 kg/s Time = 1 second
Finally, we can calculate the energy gained by the generator using the formula:
Energy = Power x Time
Energy = 1,000,000 W x 1 s Energy = 1,000,000 J
Therefore, the amount of energy gained by the generator when 339 kg of water flows through the turbine is 1,000,000 Joules.
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