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Some chlorides are hydrated.When hydrated barium chloride crystals, BaC*l_{j}*x*H_{j}*O are heated they give off water.BaC*l_{2}*x*H_{2}*O(s) -> BaC*l_{2}(s) + x*H_{2}*O(g)In an experiment, 4.88g of BaC*l_{2}*x*H_{2}*O is heated until all the water is given off. The mass of BaC*l_{2} remaining is 4.16g.[M. BaC*l_{D} 208 H_{2}*O, 18 ]Determine the value of x using the following steps. Calculate the number of moles of BaC*l_{2} remainingmolCalculate the mass of H_{2}*O given off.Calculate the number of moles of H_{2}*O given off. Determine the value of x.molx = ..[4]

Question

Some chlorides are hydrated.When hydrated barium chloride crystals, BaCl_{j}xH_{j}O are heated they give off water.BaCl_{2}xH_{2}O(s) -> BaCl_{2}(s) + xH_{2}O(g)In an experiment, 4.88g of BaCl_{2}xH_{2}O is heated until all the water is given off. The mass of BaCl_{2} remaining is 4.16g.[M. BaC*l_{D} 208 H_{2}O, 18 ]Determine the value of x using the following steps. Calculate the number of moles of BaCl_{2} remainingmolCalculate the mass of H_{2}*O given off.Calculate the number of moles of H_{2}*O given off. Determine the value of x.molx = ..[4]

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Solution

Sure, here are the steps to determine the value of x:

  1. Calculate the number of moles of BaCl2 remaining: The molar mass of BaCl2 is 208 g/mol. So, the number of moles = mass/molar mass = 4.16g / 208 g/mol = 0.02 mol.

  2. Calculate the mass of H2O given off: The mass of H2O given off = initial mass - final mass = 4.88g - 4.16g = 0.72g.

  3. Calculate the number of moles of H2O given off: The molar mass of H2O is 18 g/mol. So, the number of moles = mass/molar mass = 0.72g / 18 g/mol = 0.04 mol.

  4. Determine the value of x: x = moles of H2O / moles of BaCl2 = 0.04 mol / 0.02 mol = 2.

So, the value of x is 2.

This problem has been solved

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