If crystal oscillator parameters are as follows: R = 5K Ohm, L = 0.5H, Cs = 0.06pF, Cp = 1pF, then what is the difference between two frequencies of oscillations?a.27KHzb.21KHzc.36KHzd.25KHz

The difference between two frequencies of oscillations can be calculated using the formula for the resonant frequency of a crystal oscillator. The resonant frequency is given by the formula:

f = 1 / (2π √(LC))

where L is the inductance, C is the capacitance, and f is the frequency.

In this case, we have two capacitances: Cs (series capacitance) and Cp (parallel capacitance). Therefore, we have two frequencies of oscillation.

The series resonant frequency (fs) is given by:

fs = 1 / (2π √(L*Cs))

The parallel resonant frequency (fp) is given by:

fp = 1 / (2π √(L*(Cs*Cp / (Cs + Cp))))

The difference between the two frequencies is then:

Δf = fp - fs

Substituting the given values:

fs = 1 / (2π √(0.50.0610^-12)) = 9.2 MHz fp = 1 / (2π √(0.5*(0.06*1 / (0.06 + 1))*10^-12)) = 9.23 MHz

Δf = 9.23 MHz - 9.2 MHz = 0.03 MHz = 30 KHz

So, none of the options given (a. 27KHz, b. 21KHz, c. 36KHz, d. 25KHz) match the calculated difference. Please check the values or the options again.