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What will be the output of the following Python code?s1={3, 4}s2={1, 2}s3=set()i=0j=0for i in s1: for j in s2: s3.add((i,j)) i+=1 j+=1print(s3) {(3, 4), (1, 2)}Error{(4, 2), (3, 1), (4, 1), (5, 2)}{(3, 1), (4, 2)}

Question

What will be the output of the following Python code?s1={3, 4}s2={1, 2}s3=set()i=0j=0for i in s1: for j in s2: s3.add((i,j)) i+=1 j+=1print(s3) {(3, 4), (1, 2)}Error{(4, 2), (3, 1), (4, 1), (5, 2)}{(3, 1), (4, 2)}

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Solution

The output of the given Python code will be {(4, 2), (3, 1), (4, 1), (5, 2)}.

Here's the step by step explanation:

  1. We have three sets s1, s2, and s3. s1 contains elements 3 and 4, s2 contains elements 1 and 2, and s3 is an empty set.

  2. We have two variables i and j, both initialized to 0.

  3. We start a for loop where i iterates over the elements of s1. For each i in s1, we start another for loop where j iterates over the elements of s2.

  4. In the inner loop, we add the tuple (i, j) to s3, then increment i and j by 1.

  5. After all iterations, we print s3.

  6. The output will be {(4, 2), (3, 1), (4, 1), (5, 2)} because for each element i in s1 and for each element j in s2, we add the tuple (i, j) to s3 and then increment i and j. So the tuples added to s3 will be (3, 1), (4, 2) for the first iteration of i, and (4, 1), (5, 2) for the second iteration of i.

This problem has been solved

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