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The following reaction goes to 80% completion in a CSTR. A and B are fed to the reactor at rates of 2mol/s and 3 mol/s respectively at a temperature of 370C. Specific heats (in J/mol-K) of A, B, C and Dare 200, 150, 220 and 180 respectively.A B C D  The reactor is jacketed by water at a temperature of 200C. The overall heat transfer coefficient hasbeen estimated at 300 J/(m2.s.K), while the heat transfer area is 0.75 m2. Mixing is ensured throughan agitator, which contributes a work of 12 kW to the reactor. The heat of reaction is -30 kJ/mole ofA at 300 K. Calculate the steady state temperature in the reactor

Question

The following reaction goes to 80% completion in a CSTR. A and B are fed to the reactor at rates of 2mol/s and 3 mol/s respectively at a temperature of 370C. Specific heats (in J/mol-K) of A, B, C and Dare 200, 150, 220 and 180 respectively.A B C D  The reactor is jacketed by water at a temperature of 200C. The overall heat transfer coefficient hasbeen estimated at 300 J/(m2.s.K), while the heat transfer area is 0.75 m2. Mixing is ensured throughan agitator, which contributes a work of 12 kW to the reactor. The heat of reaction is -30 kJ/mole ofA at 300 K. Calculate the steady state temperature in the reactor

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Solution

To solve this problem, we need to apply the energy balance equation for a CSTR (Continuous Stirred-Tank Reactor). The general form of the energy balance equation is:

Q + Ws = ΔH + ΔU

where:

  • Q is the heat transferred to the system,
  • Ws is the shaft work or the work done by the agitator,
  • ΔH is the change in enthalpy of the system,
  • ΔU is the change in internal energy of the system.

Given that the reaction is exothermic (heat of reaction is negative), the heat will be removed from the reactor. Also, since the reactor is at steady state, the change in internal energy (ΔU) is zero. Therefore, the energy balance equation simplifies to:

Q + Ws = ΔH

The heat transferred to the system (Q) can be calculated using the formula:

Q = UA(Tj - Tr)

where:

  • U is the overall heat transfer coefficient,
  • A is the heat transfer area,
  • Tj is the jacket temperature,
  • Tr is the reactor temperature.

The work done by the agitator (Ws) is given as 12 kW.

The change in enthalpy of the system (ΔH) can be calculated using the formula:

ΔH = Σνi*ΔHi

where:

  • νi is the stoichiometric coefficient of species i,
  • ΔHi is the change in enthalpy of species i.

The change in enthalpy of species i (ΔHi) can be calculated using the formula:

ΔHi = Cp,i*(T - Tref)

where:

  • Cp,i is the specific heat capacity of species i,
  • T is the temperature,
  • Tref is the reference temperature.

By substituting the given values into the above equations, we can solve for the reactor temperature (Tr). However, this will require some numerical calculations which are not possible to perform here.

This problem has been solved

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