Problem Statement:- In a Conference ,attendees are invited for a dinner after the conference.TheCo-ordinator,Sagar arranged around round tables for dinner and want to have an impactfulseating experience for the attendees.Before finalizing the seating arrangement,he wants toanalyze all the possible arrangements.These are R round tables and N attendees.In case where Nis an exact multiple of R,the number of attendees must be exactly N//R,,If N is not an exactmultiple of R, then the distribution of attendees must be as equal as possible.Please refer to theexample section before for better understanding.For example, R = 2 and N = 3All possible seating arrangements are(1,2) & (3)(1,3) & (2)(2,3) & (1)Attendees are numbered from 1 to N.Input Format:● The first line contains T denoting the number of test cases.● Each test case contains two space separated integers R and N, Where R denotes thenumber of round tables and N denotes the number of attendees.Output Format:Single Integer S denoting the number of possible unique arrangements.Constraints:● 0 <= R <= 10(Integer)● 0 < N <= 20 (Integer)Sample Input 1:12 5Sample Output 1:10Explanation:R = 2, N = 5(1,2,3) & (4,5)(1,2,4) & (3,5)(1,2,5) & (3,4)(1,3,4) & (2,5)(1,3,5) & (2,4)(1,4,5) & (2,3)(2,3,4) & (1,5)(2,3,5) & (1,4)(2,4,5) & (1,3)(3,4,5) & (1,2)Arrangements like(1,2,3) & (4,5)(2,1,3) & (4,5)(2,3,1) & (4,5) etc.But as it is a round table,all the above arrangements are same.
Question
Problem Statement:- In a Conference ,attendees are invited for a dinner after the conference.TheCo-ordinator,Sagar arranged around round tables for dinner and want to have an impactfulseating experience for the attendees.Before finalizing the seating arrangement,he wants toanalyze all the possible arrangements.These are R round tables and N attendees.In case where Nis an exact multiple of R,the number of attendees must be exactly N//R,,If N is not an exactmultiple of R, then the distribution of attendees must be as equal as possible.Please refer to theexample section before for better understanding.For example, R = 2 and N = 3All possible seating arrangements are(1,2) & (3)(1,3) & (2)(2,3) & (1)Attendees are numbered from 1 to N.Input Format:● The first line contains T denoting the number of test cases.● Each test case contains two space separated integers R and N, Where R denotes thenumber of round tables and N denotes the number of attendees.Output Format:Single Integer S denoting the number of possible unique arrangements.Constraints:● 0 <= R <= 10(Integer)● 0 < N <= 20 (Integer)Sample Input 1:12 5Sample Output 1:10Explanation:R = 2, N = 5(1,2,3) & (4,5)(1,2,4) & (3,5)(1,2,5) & (3,4)(1,3,4) & (2,5)(1,3,5) & (2,4)(1,4,5) & (2,3)(2,3,4) & (1,5)(2,3,5) & (1,4)(2,4,5) & (1,3)(3,4,5) & (1,2)Arrangements like(1,2,3) & (4,5)(2,1,3) & (4,5)(2,3,1) & (4,5) etc.But as it is a round table,all the above arrangements are same.
Solution
To solve this problem, we need to find all possible seating arrangements for the attendees at the dinner. The input consists of the number of test cases, followed by the number of round tables (R) and the number of attendees (N) for each test case.
To start, we need to iterate through each test case. For each test case, we will calculate the number of possible unique arrangements.
If N is an exact multiple of R, then the number of attendees per table will be N//R. We can simply calculate the number of unique arrangements by finding the factorial of N//R and raising it to the power of R.
If N is not an exact multiple of R, we need to distribute the attendees as equally as possible. To do this, we will distribute the remaining attendees one by one to each table until there are no more remaining attendees. We will calculate the number of unique arrangements using the same method as before.
Finally, we will output the total number of possible unique arrangements for each test case.
Let's go through the example given in the problem statement: R = 2 and N = 3.
All possible seating arrangements are: (1,2) & (3) (1,3) & (2) (2,3) & (1)
Since R = 2 and N = 3, the number of attendees per table is 3//2 = 1. We have 3 attendees and 2 tables, so the number of unique arrangements is 3!^2 = 6.
Therefore, the output for this example is 6.
We will follow the same steps for all test cases and output the total number of possible unique arrangements for each case.
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