What is the specific latent heat of a 10.0mg object that transfers 740mJ during a change of state?
Question
What is the specific latent heat of a 10.0mg object that transfers 740mJ during a change of state?
Solution
The specific latent heat (L) of a substance is the amount of heat energy required to change the state of a unit mass of the substance without a change in temperature. It is given by the formula:
L = Q / m
where:
- L is the specific latent heat,
- Q is the heat energy transferred,
- m is the mass of the substance.
In this case, we are given:
- Q = 740 mJ = 740 * 10^-3 J (since 1 mJ = 10^-3 J),
- m = 10.0 mg = 10.0 * 10^-6 kg (since 1 mg = 10^-6 kg).
Substituting these values into the formula, we get:
L = (740 * 10^-3) / (10.0 * 10^-6) = 74000 J/kg.
So, the specific latent heat of the object is 74000 J/kg.
Similar Questions
What is the mass of an object with specific latent heat 199000J/kg that takes 1.09MJ to change state?
If 50 kJ of heat are removed from the substance when it is at 50oC, what will be the state and temperature of the substance?
What is the temperature change when 2.5×10 4 J is transferred to a 0.50kg object with a specific heat capacity of 1000J/(kg ∘ C)?
5.0GJ of energy is absorbed by 1.25×10 4 kg of a pure metal at its melting point. It melts and no temperature change is recorded. What is the latent heat of fusion of this metal?
1695 kJ of energy is transferred to water at 100 °CThe specific latent heat of vaporisation of water is 2.260 × 10 6 J / kgCalculate the mass of water changed into a gas at 100 °CEnergy transferred = mass x specific latent heat
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.