Suppose you have a inode-based file system having 32-byte blocks and the file block pointers are 32 bits. The inode contains exactly 1 indirect pointer and 1 doubly indirect pointer. How many direct pointers are needed to support a file size of 3200 bytes?

To calculate the number of direct pointers needed to support a file size of 3200 bytes, we first need to understand the structure of an inode-based file system.

1. In an inode-based file system, each file is represented by an inode, which contains metadata about the file, including the location of its data blocks on the disk.

2. The size of each block in this file system is 32 bytes.

3. The file size we are interested in is 3200 bytes.

4. To calculate the number of blocks needed to store this file, we divide the file size by the block size: 3200 bytes / 32 bytes/block = 100 blocks.

5. Each block pointer is 32 bits, and each block can contain 32 bytes. Therefore, each block can contain 32 bytes / 4 bytes (32 bits) = 8 block pointers.

6. The inode contains 1 indirect pointer and 1 doubly indirect pointer. The indirect pointer points to a block that contains direct pointers to the file's data blocks. The doubly indirect pointer points to a block that contains pointers to blocks, each of which contains direct pointers to the file's data blocks.

7. However, the question asks for the number of direct pointers needed, so we don't need to consider the indirect and doubly indirect pointers.

8. Therefore, the number of direct pointers needed to support a file size of 3200 bytes is equal to the number of blocks needed to store the file, which is 100.