Sure, let's break it down:

1. First, we need to calculate (1+i)^10. Using the binomial theorem, we get (1+i)^10 = 1 + 10i - 45 - 120i + 210 + 252i - 210 - 120i + 45 + 10i - 1 = -60i.

2. Next, we calculate (1-1)^10. Any number raised to the power of 10 is 0, so (1-1)^10 = 0^10 = 0.

3. Finally, we add the two results together: -60i + 0 = -60i.

So, the complex number (1+i)^10 + (1-1)^10 is -60i.

Question

Sure, let's break it down:

1. First, we need to calculate (1+i)^10. Using the binomial theorem, we get (1+i)^10 = 1 + 10i - 45 - 120i + 210 + 252i - 210 - 120i + 45 + 10i - 1 = -60i.

2. Next, we calculate (1-1)^10. Any number raised to the power of 10 is 0, so (1-1)^10 = 0^10 = 0.

3. Finally, we add the two results together: -60i + 0 = -60i.

So, the complex number (1+i)^10 + (1-1)^10 is -60i.

Knowee AI · Accepted Answer

Sure, let's break it down:

1. First, we need to calculate (1+i)^10. Using the binomial theorem, we get (1+i)^10 = 1 + 10i - 45 - 120i + 210 + 252i - 210 - 120i + 45 + 10i - 1 = -60i.

2. Next, we calculate (1-1)^10. Any number raised to the power of 10 is 0, so (1-1)^10 = 0^10 = 0.

3. Finally, we add the two results together: -60i + 0 = -60i.

So, the complex number (1+i)^10 + (1-1)^10 is -60i.

Find the complex number (1+i) 10 + (1-1)10

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