In ΔIJK, i = 3.3 inches, k = 7 inches and ∠K=117°. Find all possible values of ∠I, to the nearest 10th of a degree.
Question
In ΔIJK, i = 3.3 inches, k = 7 inches and ∠K=117°. Find all possible values of ∠I, to the nearest 10th of a degree.
Solution 1
To solve this problem, we will use the Law of Cosines. The Law of Cosines states that for any triangle with sides of lengths a, b, and c, and an angle γ opposite side c, the following relationship holds:
c² = a² + b² - 2ab cos(γ)
In this case, we know the lengths of sides i and k, and the measure of ∠K. We can rearrange the Law of Cosines to solve for cos(γ):
cos(γ) = (a² + b² - c²) / (2ab)
Substituting the given values:
cos(∠I) = (i² + k² - j²) / (2ik) cos(∠I) = (3.3² + 7² - j²) / (2 * 3.3 * 7)
We don't know the length of side j, but we do know that ∠K = 117°. We can use the Law of Sines to find j:
sin(∠K) = j / k j = k * sin(∠K) j = 7 * sin(117°)
Substitute j back into the equation for cos(∠I):
cos(∠I) = (3.3² + 7² - (7 * sin(117°))²) / (2 * 3.3 * 7)
Solve for ∠I:
∠I = arccos[((3.3² + 7² - (7 * sin(117°))²) / (2 * 3.3 * 7))]
This will give you the measure of ∠I in degrees. Note that because the arccos function returns values between 0° and 180°, there may be two possible values for ∠I. To find the second possible value, subtract the first value from 180°.
Solution 2
To solve this problem, we will use the Law of Sines, which states that the ratio of the length of a side of a triangle to the sine of the angle opposite that side is the same for all three sides of the triangle.
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First, we find the sine of ∠K: sin(117°) = 0.8910 (rounded to the nearest four decimal places).
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Next, we set up the ratio of side k to the sine of ∠K, and set it equal to the ratio of side i to the sine of ∠I:
7/sin(117°) = 3.3/sin(∠I)
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Solving for sin(∠I), we get:
sin(∠I) = 3.3 * sin(117°) / 7 = 0.4180 (rounded to the nearest four decimal places).
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Now, we find ∠I by taking the inverse sine (also known as arcsin) of 0.4180:
∠I = arcsin(0.4180) = 24.9° (rounded to the nearest tenth of a degree).
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However, there is another possible value for ∠I. Since the sine function has a period of 360° and is positive in both the first and second quadrants, ∠I could also be 180° - 24.9° = 155.1°.
So, the possible values for ∠I are 24.9° and 155.1°.
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