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While presenting a data in the form of a positive number, I committed a mistake by mentioning the cube of the number. If the error due to this mistake was 800%, what was the number?2534

Question

While presenting a data in the form of a positive number, I committed a mistake by mentioning the cube of the number. If the error due to this mistake was 800%, what was the number?2534

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Solution

The problem is asking for a number that, when cubed, is 800% larger than the original number.

To solve this, we need to understand that an 800% increase of a number is the same as multiplying that number by 9 (since 100% of a number is the number itself, 800% is 8 times the number, plus the original number equals 9 times the original number).

So, if x is the original number, and y is the number when cubed, the problem can be represented as:

y = 9x

But we also know that y is equal to x cubed (from the problem statement), so we can also say:

x^3 = 9x

To solve for x, we can divide both sides of the equation by x to get:

x^2 = 9

Taking the square root of both sides gives:

x = 3

So, the original number was 3.

This problem has been solved

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