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If f(2)=13๐‘“(2)=13, which could be the equation for f(x)๐‘“(๐‘ฅ)? f(x)=2x3+5๐‘“(๐‘ฅ)=2๐‘ฅ3+5 f(x)=x+x2๐‘“(๐‘ฅ)=๐‘ฅ+๐‘ฅ2 f(x)=3x2+1๐‘“(๐‘ฅ)=3๐‘ฅ2+1 f(x)=x2+8๐‘“(๐‘ฅ)=๐‘ฅ2+8

Question

If f(2)=13๐‘“(2)=13, which could be the equation for f(x)๐‘“(๐‘ฅ)? f(x)=2x3+5๐‘“(๐‘ฅ)=2๐‘ฅ3+5 f(x)=x+x2๐‘“(๐‘ฅ)=๐‘ฅ+๐‘ฅ2 f(x)=3x2+1๐‘“(๐‘ฅ)=3๐‘ฅ2+1 f(x)=x2+8๐‘“(๐‘ฅ)=๐‘ฅ2+8

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Solution

The question seems to be asking which of the given equations would result in f(2) = 13. We can find this by substituting x = 2 into each equation and seeing which one gives us 13.

  1. f(x) = 2x^3 + 5. Substituting x = 2, we get f(2) = 2*(2^3) + 5 = 2*8 + 5 = 16 + 5 = 21. So, this equation does not give us f(2) = 13.

  2. f(x) = x + x^2. Substituting x = 2, we get f(2) = 2 + (2^2) = 2 + 4 = 6. So, this equation does not give us f(2) = 13.

  3. f(x) = 3x^2 + 1. Substituting x = 2, we get f(2) = 3*(2^2) + 1 = 3*4 + 1 = 12 + 1 = 13. So, this equation does give us f(2) = 13.

  4. f(x) = x^2 + 8. Substituting x = 2, we get f(2) = (2^2) + 8 = 4 + 8 = 12. So, this equation does not give us f(2) = 13.

So, the equation that could be for f(x) given that f(2) = 13 is f(x) = 3x^2 + 1.

This problem has been solved

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