a single-phase transformer has a turn ratio of 1:2 and is connected to a purely resistive load.the magnetizing current drawn is 1a.if core losses and leakage reactance are neglected, the primary current is-1.41a2a2.24a3a
Question
a single-phase transformer has a turn ratio of 1:2 and is connected to a purely resistive load.the magnetizing current drawn is 1a.if core losses and leakage reactance are neglected, the primary current is-1.41a2a2.24a3a
Solution
The primary current in a transformer is the sum of the magnetizing current and the load current.
Given that the transformer has a turn ratio of 1:2, this means that the voltage is stepped up by a factor of 2, and the current is stepped down by the same factor.
If the load is purely resistive, the load current on the secondary side will be in phase with the voltage.
Assuming a secondary current of 1A (since the current is stepped down by a factor of 2), the primary current will be the secondary current divided by the turn ratio, or 1A/2 = 0.5A.
Adding the magnetizing current of 1A, the total primary current is 1A + 0.5A = 1.5A.
However, the given options do not include 1.5A. This could be due to a mistake in the problem statement or the given options.
Please check the problem statement and the given options. If the problem statement and the options are correct, then the answer is not among the given options.
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