NumbersWhen two numbers are separately divided by 33, the remainders are 21 and 28 respectively. If the sum of the two numbers is divided by 33, the remainder will beOptions12101416
Question
NumbersWhen two numbers are separately divided by 33, the remainders are 21 and 28 respectively. If the sum of the two numbers is divided by 33, the remainder will beOptions12101416
Solution
To solve this problem, we can use the concept of modular arithmetic.
Let's call the two numbers x and y. We know that when x is divided by 33, the remainder is 21, and when y is divided by 33, the remainder is 28.
Using modular arithmetic, we can express these conditions as equations: x ≡ 21 (mod 33) y ≡ 28 (mod 33)
Now, we need to find the remainder when the sum of x and y is divided by 33. We can express this as: (x + y) ≡ ? (mod 33)
To find the remainder, we can add the two equations together: (x + y) ≡ (21 + 28) (mod 33) (x + y) ≡ 49 (mod 33)
Now, we need to simplify the right side of the equation. Since 49 is divisible by 33, we can express it as: (x + y) ≡ 16 (mod 33)
Therefore, the remainder when the sum of the two numbers is divided by 33 is 16.
So, the correct option is 16.
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