Calculate the mass of NaCl needed to prepare 1.50 L of 0.250 M NaClGroup of answer choices0.375 g21.9 g58.44 g0.250 g
Question
Calculate the mass of NaCl needed to prepare 1.50 L of 0.250 M NaClGroup of answer choices0.375 g21.9 g58.44 g0.250 g
Solution
To calculate the mass of NaCl needed, we can use the formula for molarity which is:
Molarity (M) = moles of solute / liters of solution
We know the molarity (0.250 M) and the volume of the solution (1.50 L), and we need to find the moles of solute (NaCl).
Rearranging the formula, we get:
Moles of solute = Molarity * liters of solution = 0.250 M * 1.50 L = 0.375 moles of NaCl
Next, we need to convert moles to grams. The molar mass of NaCl is approximately 58.44 g/mol.
So, the mass of NaCl needed is:
Mass = moles * molar mass = 0.375 moles * 58.44 g/mol = 21.9 g
So, the mass of NaCl needed to prepare 1.50 L of 0.250 M NaCl is 21.9 g.
Similar Questions
Molar mass of NaCl is ___________Group of answer choices40.00 g/mol58.44 g/mol22.99 g/mol35.45 g/mol
If 5.00 g of NaCl are dissolved in 25.0 g of water, the percent mass (m/m) of this soluton isGroup of answer choices15516.7200.2
A second-year chemistry student is asked to make up a 250.0 mL sample of 5.87 M aqueous sodium chloride, NaCl solution.Molar mass of NaCl = 58.44 g mol-1 (a) Calculate the mass (in grams) of solid sodium chloride that the student would need to weigh out. Provide your numerical answers and units. (b) The student is then asked to make up 100.0 mL of sodium chloride solution using 15.00 mL of the 5.87 M NaCl solution made up in part (a). The diluted solution is then mixed completely. Determine the concentration of the diluted sodium chloride solution.
1. What is the mass of 7.200 × 1025 formula units of salt (NaCl)?
What is the mass of sodium chloride produced when g of sodium is reacted with g of chlorine?Na + Cl NaClQuestion 15Select one:a.10.510.5 g NaClb.7.47.4 g NaClc.2121 g NaCld.3.73.7 g NaCl
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.