A student was asked to find a 95% confidence interval for the proportion of students who take notes using data from a random sample of size n = 89. Which of the following is a correct interpretation of the interval 0.1 < p < 0.2?Check all that are correct.There is a 95% chance that the proportion of notetakers in a sample of 89 students will be between 0.1 and 0.2.There is a 95% chance that the proportion of the population is between 0.1 and 0.2.With 95% confidence, the proportion of all students who take notes is between 0.1 and 0.2.With 95% confidence, a randomly selected student takes notes in a proportion of their classes that is between 0.1 and 0.2.The proprtion of all students who take notes is between 0.1 and 0.2, 95% of the time.

A student was asked to find a 98% confidence interval for widget width using data from a random sample of size n = 27. Which of the following is a correct interpretation of the interval 13.5 < μ < 22?Check all that are correct.There is a 98% chance that the mean of the population is between 13.5 and 22.With 98% confidence, the mean width of a randomly selected widget will be between 13.5 and 22.There is a 98% chance that the mean of a sample of 27 widgets will be between 13.5 and 22.With 98% confidence, the mean width of all widgets is between 13.5 and 22.The mean width of all widgets is between 13.5 and 22, 98% of the time. We know this is true because the mean of our sample is between 13.5 and 22.

A student was asked to find a 95% confidence interval for weight of their backpacks in pounds using data from a random sample of size n = 20. Which of the following is a correct interpretation of the interval 3.1 < μ < 8.6? Assume the population is normally distributed.With 95% confidence, the weight of a randomly selected backpack will be between 3.1 and 8.6 pounds.There is a 95% chance that the mean of a sample of 20 backpacks will weigh between 3.1 and 8.6 pounds.There is a 95% chance that the weight is between 3.1 and 8.6.With 95% confidence, the mean weight of all backpacks is between 3.1 and 8.6 pounds.The sample mean weight of all backpacks is between 3.1 and 8.6 pounds, 95% of the time. We know this is true because the mean of our sample is between 3.1 and 8.6.

A sample of size =n92 is drawn from a normal population whose standard deviation is =σ5.1. The sample mean is =x35.33.Part 1 of 2(a) Construct a 99.9% confidence interval for μ. Round the answer to at least two decimal places.A 99.9% confidence interval for the mean is 33.58<<μ37.08.Part: 1 / 21 of 2 Parts CompletePart 2 of 2(b) If the population were not approximately normal, would the confidence interval constructed in part (a) be valid? Explain.The confidence interval constructed in part (a) ▼(Choose one) be valid since the sample size ▼(Choose one) larg

Suppose (35,40) is a 95% confidence interval estimate for a population mean 𝜇. Which of the following are true statements?I. There is a .95 probability that 𝜇 is between 35 and 40.II. If 100 random samples of the given size are picked and a 95% confidence interval is calculated from each, then 𝜇 will be in 95 of the resulting intervals.III. If 95% confidence intervals are calculated from all possible samples of the given size, 𝜇 will be in 95% of these intervals.I and III and IIIII and IIII, II, and IIINone of the above gives the complete set of true responses.

A random sample of 160 households is selected to estimate the mean amount spent on electric service. A 95% confidence interval was determined from the sample results to be ($151, $216). Which of the following is the correct interpretation of this interval? There is a 95% chance that the mean amount spent on electric service is between $151 and $216. We are 95% confident that the mean amount spent on electric service among the 160 households is between $151 and $216. 95% of the households will have an electric bill between $151 and $216. We are 95% confident that the mean amount spent on electric service among all households is between $151 and $216